openstack tenant中role的显示
在IP/identity/users的页面中，想要显示每个user属于的tenant,并给出这个tenant中的各个role。这里主要是要注意调用api时，尽量少的进行for循环，此处给出两种情况，在现实情况中，由于进行http的访问不同，所以页面加载速度差距很大：
fortenants_one in tenants:
user_roles = api.keystone.get_project_users_roles(self.request,tenants_one.id)
dict_user_roles = user_roles
user_roles = []
# import pdb
# pdb.set_trace()
for user_one in userslist:
for tenants_one in tenants:
if user_one['id'] in dict_user_roles.keys():
role_id = dict_user_roles]
for roleid_element in role_id:
for role_element in roles:
if roleid_element == role_element.id:
r_name.append(role_element.name)
if r_name !=[]:
str_project_role = str_project_role + tenants_one.name + ':'
for x in r_name:
str_project_role = str_project_role + x + ','+''
str_project_role = str_project_role + ''
r_name = []
user_one['prorole'] = str_project_role
str_project_role = ''
# user_s1 = users
# for user_one in userslist:
# for tenants_one in tenants:
# # str_project_role = ''
# # str_project_role = str_project_role+tenants_one.name + ':'
# user_roles = api.keystone.get_project_users_roles(self.request,tenants_one.id)
# if user_one['id'] in user_roles.keys():
# role_id = user_roles]
# for roleid_element in role_id:
# for role_element in roles:
# if roleid_element == role_element.id:
# r_name.append(role_element.name)
# # r_name.append(roles)
# if r_name != []:
# dict1 = r_name
# LL.append(dict1)
# # for x in r_name:
# # str_project_role = ' ' + str_project_role + x
# # str_projcet_role =
# str_project_role = str_project_role + tenants_one.name + ':'
# for x in r_name:
# str_project_role = str_project_role + x + ','
# str_project_role = str_project_role + ' ;'
# r_name = []
# dict1 ={}
# # user_one = LL
# user_one['prorole'] = str_project_role
# str_project_role = ''
# LLL.append(LL)
# LL = []
其中注释掉的代码，非常糟糕，仅供参考理解
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