python split多个分隔符
1.split不支持同时使用多种字符做分隔符，如果想实现这样的效果，可以用re，例如：>>> s = 'Hello!This?Is!What?I!Want'
>>> s
'Hello!This?Is!What?I!Want'
>>> re.split('[!?]',s)
['Hello', 'This', 'Is', 'What', 'I', 'Want']
i = "25 192.168.19.32 192.168.1.30 env -i X='() { (a)=>\' bash -c 'echo date'; cat echo"
>>> re.split(r'[ \[\]]',i)
['25', '192.168.19.32', '192.168.1.30', '', '2014.09.28', '09:01:35', 'env', '-i
', "X='()", '{', "(a)=>'", 'bash', '-c', "'echo", "date';", 'cat', 'echo']
>>> re.findall(r'[\w.:]+',i)
['25', '192.168.19.32', '192.168.1.30', '2014.09.28', '09:01:35', 'env', 'i', 'X
', 'a', 'bash', 'c', 'echo', 'date', 'cat', 'echo']
>>> re.findall(r'[^]^[\s]+',i)
['25', '192.168.19.32', '192.168.1.30', '2014.09.28', '09:01:35', 'env', '-i', "
X='()", '{', "(a)=>'", 'bash', '-c', "'echo", "date';", 'cat', 'echo']
2.例子
test.txt:
abcdstr1
astr2m supernbajack
jordon
#coding: utf-8
import re
def split_on_separators(original, separators):
# 这个是用正则实现的，可能不满足要求，不过非常简单
# return filter(lambda x:x.strip(), re.split(r"[%s]" % separators, original))
result =
for sep in separators:
temp = []
for r in result:
temp.extend(filter(lambda x:x.strip(), r.split(sep)))
result = temp
return result
if __name__ == "__main__":
line = open('test.txt','r').read()
print split_on_separators(line, "\t\n")
#print split_on_separators("a\tb\nc\tdstr1\nastr2 a\tlisa", "\t\n")
打印结果：
['a', 'b', 'c', 'dstr1', 'astr2', 'm super', 'nba', 'jack', 'jordon']
————————————————————
for r in result:
temp.extend(filter(lambda x:x.strip(), r.split(sep)))
对这句的理解：
>>> a = ' 123\ra\tabc'
>>> a.strip()
'123\ra\tabc'
>>>filter(lambda x:x.strip(),' 123\ra\tabc')
'123aabc'
>>> filter(lambda x:x.strip(),'a\tb\nc\tdstr1\nastr2 a\tlisa')
'abcdstr1astr2alisa'
>>> b = filter(lambda x:x.strip(),'')
>>> b
''
>>> temp = []
>>> temp.extend(filter(lambda x:x.strip(),'a'.split('\n\t')))
>>> temp
['a']
>>> temp
['a']
>>> temp.extend(filter(lambda x:x.strip(),'str1'.split('\n\t')))
>>> temp
['a', 'str1']
>>> temp.extend(filter(lambda x:x.strip(),'str2'))
>>> temp
['a', 'str1', 's', 't', 'r', '2']
>>> temp = []
>>> temp.extend(filter(lambda x:x.strip(),' 123\ra\tabc'))
>>> temp
['1', '2', '3', 'a', 'a', 'b', 'c']
>>> temp.extend(filter(lambda x:x.strip(),' 123\ra\tabc'.split('\n\t')))
>>> temp
['1', '2', '3', 'a', 'a', 'b', 'c', ' 123\ra\tabc']
——————————————————————————————————
上面例子的应用，将含有多列的普通文本写到excel中（本例split分隔符为空格和\n）：
#coding: utf-8
import re,xlrd,xlwt
def split_on_separators(original, separators):
# 这个是用正则实现的，可能不满足要求，不过非常简单
# return filter(lambda x:x.strip(), re.split(r"[%s]" % separators, original))
result =
for sep in separators:
temp = []
for r in result:
temp.extend(filter(lambda x:x.strip(), r.split(sep)))
result = temp
return result
line = open('ex.txt','r').read()
lisa = split_on_separators(line, " \n")
def wexcel(infile,outefile):
buf = lisa
print buf
w=xlwt.Workbook()
sheet=w.add_sheet('sheet1')
for i in range(len(buf)):
print buf
sheet.write(i,0,buf.decode('utf8'))
w.save(outefile)
wexcel('ex.txt','ex.xls')
打印结果(ex.txt写到ex.xls中)：
ex.txt：
/ 24%
/backup 62%
/project 20%
memory 26.16%
————————————————后续———————————————
test.txt：
/ 24%
/backup 62%
/project 20%
memory 26.16%
line = file('D:/python27/test.txt','r').read()
>>> line.split('\n')
['/ 24%', '/backup 62%', '/project 20%'
, 'memory 26.16%']
>>> line.split()
['/', '24%', '/backup', '62%', '/project', '20%', 'memory', '26.16%']
>>> filter(lambda x:x.strip(),line.split())
['/', '24%', '/backup', '62%', '/project', '20%', 'memory', '26.16%']
>>> for i in :
... print i.split('\n')
...
['/ 24%', '/backup 62%', '/project 20%'
, 'memory 26.16%']
>>> for i in :
... print filter(lambda x:x.strip(), i.split('\n'))
...
['/ 24%', '/backup 62%', '/project 20%'
>>> filter(lambda x:x.strip(),line)
'/24%/backup62%/project20%memory26.16%'
>>> for i in line.split('\n'):
... for sep in i.split(' '):
... temp = []
... temp.extend(filter(lambda x:x.strip(),i.split(' ')))
... print temp
...
['/', '24%']
['/backup', '62%']
['/project', '20%']
['memory', '26.16%']
>>> for i in line.split('\n'):
... for sep in i.split(' '):
... temp = []
... temp.extend(filter(lambda x:x.strip(),sep.split(' ')))
... print sep
...
24%
62%
20%
26.16%
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