shell的部分习题(持续更新)
#!/bin/bash#
#
read -p "Input your the month of yourbirthday,the format such as 05 :" Birthmonth
while [[ ! "$Birthmonth" =~ || $Birthmonth -lt 1 || $Birthmonth -gt 12 ]];do
//判断用户是否输入两位数字，个位数需用零补全
read -p "Input two digits,the value must between in 01 and 12,such as 04 :" Birthmonth
done
read -p "Input your the day of your birthday,the format such as 25 : " Birthday
until [[ $Birthday =~ && $Birthday -gt 0 && $Birthday -le 31 ]];do
read -p "Input two digits,and the value must in 01 and 31,such as 25 :" Birthday
done
Year=`date +%Y` //定义变量，简化后续引用
J=`date +%s`
if [ $Birthmonth$Birthday -eq `date +%m%d` ];then //if判断如果生日与现在时间相等
echo -e "\033[5;31mToday is your birthday,happy birthday to you.\033[0m"
elif [ $Birthmonth$Birthday -gt `date +%m%d` ];then //如果生日还未到
I=`date -d $Year$Birthmonth$Birthday +%s`
echo -e "\033[5;32m$(((($I-$J))/60/60/24+1))\033[0m days later will be your birthday"
else //else生日已过的情况
if [ $Birthmonth$Birthday -eq 0229 ];then //如果生日是2/29号
case $((`date +%Y`%4)) in //判断今年是否是闰年
0) //如果今年是闰年
I=`date -d $(($Year+4))$Birthmonth$Birthday +%s`
echo -e "\033[5;35m$(((($I-$J))/60/60/24+1))\033[0m days later will be your birthday"
;;
1)
I=`date -d $(($Year+3))$Birthmonth$Birthday +%s`
echo -e "\033[5;35m$(((($I-$J))/60/60/24+1))\033[0m days later will be your birthday"
;;
2)
I=`date -d $(($Year+2))$Birthmonth$Birthday +%s`
echo -e "\033[5;35m$(((($I-$J))/60/60/24+1))\033[0m days later will be your birthday"
;;
3)
I=`date -d $(($Year+1))$Birthmonth$Birthday +%s`
echo -e "\033[5;35m$(((($I-$J))/60/60/24+1))\033[0m days later will be your birthday"
;;
esac
else //如果生日不是2/29号
I=`date -d $(($Year+1))$Birthmonth$Birthday +%s`
echo -e "\033[5;35m$(((($I-$J))/60/60/24+1))\033[0m days later will be your birthday"
fi
fi
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