shell计算掩码位数
less maskdigits.sh#!/bin/sh
#maskdigits.sh mask
a=$(echo "$1" | awk -F "." '{print $1" "$2" "$3" "$4}')
for num in $a;
do
while (($num!=0));do
echo -n $(($num%2)) >> /tmp/$$.num;
num=$(($num/2));
done
done
echo $(grep -o "1" /tmp/$$.num | wc -l)
rm /tmp/$$.num
例如：maskdigits.sh 255.255.0.192
18
页:
[1]