Linux Shell编程实战---计算特定目录下前10个大文件
计算特定目录下前10个大文件在给定的目录下，想知道有哪些大文件存在，取前十个，按文件大小排行
(1)、使用awk来实现
#!/bin/bash
path=/root/shell
find $path-type f | awk '{
var=$0
"ls -l "var |getline var1
split(var1,a," ")
filename=a
filesize=a
printf("%s %s\n",filename,filesize)| "sort -k2 -n -r|head -10"
}
'
上面的写法在文件较多的时候可能会引起内存溢出。
改进一下如下：
#!/bin/bash
path=/root/shell
echo >r2.txt
find $path-type f | awk '{
var=$0
"ls -l "var |getline var1
split(var1,a," ")
filename=a
filesize=a
printf("%s %s\n",filename,filesize)
}
'>r2.txt
cat r2.txt|sort -k2 -n -r | head -10
(2)、使用while来实现
#!/bin/bash
path=/root/shell
echo >r1.txt
find $path-type f|while read line
do
filename=`ls -l $line|awk '{print $9}'`
filesize=`ls -l $line|awk '{print $5}'`
echo $filename $filesize>>r1.txt
done
cat r1.txt|sort -k2 -n -r | head -10
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