Bash Shell模拟密码输入
用Bash Shell来模拟密码的输入，我们先设有两个脚本，一个是praents.sh,另一个是readpass.sh。praents.sh主脚本，在praents.sh中调用readpass.sh。readpasss.sh负责密码的输入。输入一次密码，然后在输入一次密码，如果匹配错误，重新密码输入，循环3次，密码还是错误，直接退出脚本，如果密码正确，praents.sh接下去执行下面语句。我们先写readpass.sh内容脚本。如下实现功能：cat/root/Desktop/readpass.sh
#!/bin/bash
#read passwd
#sub script
function inpasswd {
read -s -p "Enter You Password:" passwd1
echo
read -s -p "Please Check Password" passwd2
echo
if [[ $passwd1 == $passwd2 ]]
then
echo "correct" && exit 1
else
echo "incorrect"
echo "Please Input Agin"
fi
}
count=1
while true
do
if [ $count -gt 3 ]
then
break
fi
inpasswd
((count++))
done
echo "Input 3 Times and exit ByeBye"
readpass.sh中的脚本，只能用于单独的运行。如果通过另外的脚本进行调用，就会发现调用的时候，如果密码匹配就会直接跳出父脚本,执行不了父脚本中下面的内容。我们的父脚本如下：
cat /root/Desktop/parents.sh
#!/bin/bash
#parents script
if [ -f /root/Desktop/readpass.sh ]
then
. /root/Desktop/readpass.sh
else
echo "No File Matching"
fi
for passwd in `cat /root/Desktop/passwd.txt`
do
echo "passwd is $passwd"
done
当parents.sh运行到. /root/Desktop/readpass.sh时，运行readpass.sh脚本，当密码匹配时，parents.sh就会退出。执行不了parents.sh下面的显示密码的语句。现在对readpass.sh进行改写:
#!/bin/bash
#read passwd
#sub script
count=1
while true
do
read -s -p "Enter You Password:" passwd1
echo
read -s -p "Please Check Password" passwd2
echo
if [[ $passwd1 == $passwd2 ]]
then
echo "$passwd1" > passwd.txt
echo "correct"
break
elif [[ $passwd1 != $passwd2 ]]
then
((count++))
if [ $count -gt 3 ]
then
echo "Input 3 Times And Exit ByeBye"
break
fi
cat /dev/null > /root/Desktop/passwd.txt
echo "incorrect"
echo "Please Input Agin"
fi
done
改写成不退出即可。
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