关于Oracle full outer join 的bug问题分析及处理
full (outer) join是用来全连接两个表的语法。即希望将A表和B表关联，能够得到A表中有而B表中没有的记录，或者B表中有而A表中没有的记录。如何判断是否有该记录，则通过on子句来关联。
下面是一个例子：
SQL> with
2A as(select 1 a, 2 b from dual),
3B as(select 2 a, 3 b from dual)
4select * from A full join B
5 on A.a=B.a
6/
A B A B
---------- ---------- ---------- ----------
1 2
2 3
了解了以上基本原理后，我们应该知道，理论上讲，A表和B表的在from子句中的顺序是没有关系的，也就是不影响结果。但是，实际上，却出现了这样的问题，下面是对这种情况的描述：
--------------------------------------------------------------------------------------------
|> --------------------------------------------------------------------------------------------
|0 | SELECT STATEMENT | | 12791 |349K| 82(3)| 00:00:01 |
|1 |VIEW | | 12791 |349K| 82(3)| 00:00:01 |
|2 |UNION-ALL | | | | | |
|*3 | FILTER | | | | | |
|*4 | HASH JOIN RIGHT OUTER| | 12790 |1124K| 41(3)| 00:00:01 |
|5 | TABLE ACCESS FULL| JXC_RISHARESUM|1735 | 78075 | 7(0)| 00:00:01 |
|6 | TABLE ACCESS FULL| JXC_ALLTRADEDAY | 12790 |562K| 33(0)| 00:00:01 |
|*7 | HASH JOIN ANTI | | 1 | 76 | 41(3)| 00:00:01 |
|*8 | TABLE ACCESS FULL | JXC_RISHARESUM| 1 | 45 | 7(0)| 00:00:01 |
|9 | TABLE ACCESS FULL | JXC_ALLTRADEDAY | 12790 |387K| 33(0)| 00:00:01 |
--------------------------------------------------------------------------------------------
从以上执行计划来看，在第四步骤，使用的是hash join rigth outer连接方式。而通过改变两表的摆放顺序，得到如下的执行计划：
-----------------------------------------------------------------------------------------
|> -----------------------------------------------------------------------------------------
|0 | SELECT STATEMENT | |1876 | 52528 | 82(3)| 00:00:01 |
|1 |VIEW | |1876 | 52528 | 82(3)| 00:00:01 |
|2 |UNION-ALL | | | | | |
|*3 | FILTER | | | | | |
|*4 | HASH JOIN OUTER| |1874 |164K| 41(3)| 00:00:01 |
|5 | TABLE ACCESS FULL| JXC_RISHARESUM|1735 | 78075 | 7(0)| 00:00:01 |
|6 | TABLE ACCESS FULL| JXC_ALLTRADEDAY | 12790 |562K| 33(0)| 00:00:01 |
|*7 | HASH JOIN ANTI | | 2 |152 | 41(3)| 00:00:01 |
|*8 | TABLE ACCESS FULL | JXC_ALLTRADEDAY | 2 | 90 | 33(0)| 00:00:01 |
|9 | TABLE ACCESS FULL | JXC_RISHARESUM|1735 | 53785 | 7(0)| 00:00:01 |
-----------------------------------------------------------------------------------------
注意，此时，执行计划中的第四个步骤，变成了：hash join outer方式。这个才是我们所期望的方式。那究竟是什么导致了这个变化呢？查看他们的谓词连接逻辑：
hash join right outer的：
3 - filter(NVL("T1"."C_SHARENO","T2"."C_SHARENO")='26200703200004969020')
4 - access("T2"."D_TRADEDATE"="T1"."D_TRADEDATE"(+) AND
"T2"."D_REGDATE"="T1"."D_REGDATE"(+) AND "T2"."C_FUNDCODE"="T1"."C_FUNDCODE"(+) AND
"T2"."C_FUNDACCO"="T1"."C_FUNDACCO"(+))
7 - access("T2"."C_FUNDACCO"="T1"."C_FUNDACCO" AND
"T2"."C_FUNDCODE"="T1"."C_FUNDCODE" AND "T2"."D_REGDATE"="T1"."D_REGDATE" AND
"T2"."D_TRADEDATE"="T1"."D_TRADEDATE")
8 - filter(NVL("T1"."C_SHARENO",NULL)='26200703200004969020')
hash join outer的：
3 - filter(NVL("T1"."C_SHARENO","T2"."C_SHARENO")='26200703200004969020')
4 - access("T2"."D_TRADEDATE"(+)="T1"."D_TRADEDATE" AND
"T2"."D_REGDATE"(+)="T1"."D_REGDATE" AND "T2"."C_FUNDCODE"(+)="T1"."C_FUNDCODE"
AND "T2"."C_FUNDACCO"(+)="T1"."C_FUNDACCO")
7 - access("T2"."C_FUNDACCO"="T1"."C_FUNDACCO" AND
"T2"."C_FUNDCODE"="T1"."C_FUNDCODE" AND "T2"."D_REGDATE"="T1"."D_REGDATE" AND
"T2"."D_TRADEDATE"="T1"."D_TRADEDATE")
8 - filter("T2"."C_SHARENO"='26200703200004969020')
还是没有发现明显的区别。但是实际却导致了结果的不同。
还原到原始的表连接顺序，然后对两表进行分析，再查看执行计划：
SQL> call dbms_stats.gather_table_stats(user, 'JXC_ALLTRADEDAY');
调用完成。
SQL> call dbms_stats.gather_table_stats(user, 'JXC_RISHARESUM');
.....
-----------------------------------------------------------------------------------------
|> -----------------------------------------------------------------------------------------
|0 | SELECT STATEMENT | |1738 | 48664 | 82(3)| 00:00:01 |
|1 |VIEW | |1738 | 48664 | 82(3)| 00:00:01 |
|2 |UNION-ALL | | | | | |
|*3 | FILTER | | | | | |
|*4 | HASH JOIN OUTER| |1735 |191K| 41(3)| 00:00:01 |
|5 | TABLE ACCESS FULL| JXC_RISHARESUM|1735 | 98895 | 7(0)| 00:00:01 |
|6 | TABLE ACCESS FULL| JXC_ALLTRADEDAY | 12775 |698K| 33(0)| 00:00:01 |
|*7 | HASH JOIN ANTI | | 3 |276 | 41(3)| 00:00:01 |
|*8 | TABLE ACCESS FULL | JXC_ALLTRADEDAY | 3 |168 | 33(0)| 00:00:01 |
|9 | TABLE ACCESS FULL | JXC_RISHARESUM|1735 | 62460 | 7(0)| 00:00:01 |
-----------------------------------------------------------------------------------------
Predicate Information (identified by operation> ---------------------------------------------------
3 - filter(NVL("T1"."C_SHARENO","T2"."C_SHARENO")='26200703200004969020')
4 - access("T2"."D_TRADEDATE"(+)="T1"."D_TRADEDATE" AND
"T2"."D_REGDATE"(+)="T1"."D_REGDATE" AND "T2"."C_FUNDCODE"(+)="T1"."C_FUNDCODE"
AND "T2"."C_FUNDACCO"(+)="T1"."C_FUNDACCO")
7 - access("T2"."C_FUNDACCO"="T1"."C_FUNDACCO" AND
"T2"."C_FUNDCODE"="T1"."C_FUNDCODE" AND "T2"."D_REGDATE"="T1"."D_REGDATE" AND
"T2"."D_TRADEDATE"="T1"."D_TRADEDATE")
8 - filter("T2"."C_SHARENO"='26200703200004969020')
可发现，这时原来连接方式的错误执行计划被修正了，改为hash join outer连接。
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