nics 发表于 2018-9-24 09:48:16

ORACLE SQL大全

简单查询  1、选择所有 select * from table;
  2、选择部分列 select column1,column2 from table;
  3、使用算数表达式 select salary+300 from emlpoyees;
  4、使用 ()select 12*(salary+20) from emlpoyees;
  5、使用列别名 select first_name Fname from employees;
  6、使用字符串连接符 select first_name || last_name from employees;
  7、过滤重复select distinct department_id from employees;
  8、where子句查询数据 select employee_id,last_name,job_id from employees where department_id=90;
  9、order by 子句排序 select last_name from employees order by hire_date;
  10、group 分组查询
  select avg (salary),
  max (salary),
  min (salary),
  sum (salary),
  count (*),
  count (commission_pct)
  from employees where job_id like ‘%REP%’;
  select department_id,
  avg (salary)
  from employees group by department_id;
  select department_id,
  max(salary)
  from employees
  group by department_id having max(salary) >10000;
  select job_id ,
  sum(salary) payroll
  from employees
  where job_id not like '%rep%'
  group by job_id having sum(salary)>13000
  order by sum(salary);
  11、子查询
  单行子查询
  select last_name
  from employees
  where salary>(select salary from employees where last_name ='Abel');
  select last_name ,job_id,salary
  from employess
  where job_id=(select job_id
  from employees
  where employee_id=141)
  and salary>(select salary
  from employees
  where employee_id=143);
  select last_name,job_id,salary
  from employess
  where salary= (select min(salary) from employees);
  select department_id,min(salary)
  from employees
  group by department_id
  having min(salary)>(select min(salary) from employees where department_id=50);
  多行子查询
  select employee_id,last_name,job_id,salary
  from employees
  where salary
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