在db1数据库中:
create table temp as select username,count(0) as num from db1_user group by username having count(0)>1;
创建temp表将用户名相同或数量大于2的找出来,保存在temp中,(本人在实际操作中,本担心group by username having count(0)>1将会导致数据库出现问题,但实际没有.很快)
create table db1_dup_user (as select t2.* from temp t1,db1_user t2
where t1.username=t2.username) default character utf8;
将用户名相同的数据全保存在db1_dup_user防止操作失误,先将数据保存起来
create table db1_single_user as select * from db1_dup_user where userid in(select min(userid) from db1_dup_user group by (username) having count(*) >1);
将id最小的多用用户名相同的保存在db1_single_use中
delete from db1_user where username in (select username from db1_single_user)
commit;
删除相同的用户名,
insert into db1_user select * from db1_single_user;
commit;
步骤2: